Digital Mathwork on PIC1320

Thread Starter

LearnPIC1234

Joined Feb 23, 2007
3
Hi all,

This is a very crucial problem for my project. I try to solve it few days ago but still no solution, hope anyone could provide me the idea or solution.


I have 3 variables in the program (Error , Kp & Control) , "Error" is signed 8 bits, "Kp" is unsigned 8 bits, "Control" is signed 16 bits variables.


Error = Error - 128 ; //read Error then subtract the offset value
Kp = Kp; //Read Kp
Control = Error * Kp; //multiply the error with the Kp

Q:

I want to use 8 bits long to represent the value of "Control", what can i do to match my requirement.


Actually the idea of this project is control an inverted pendulum by using software PID controller, "Error" is the displacement angle, minus 128 will output 0 error when pendulum is balance. "Kp" is proportional gain vary 0~255.
"Control" value will copy into PWM register, but the PWM register is an 8bits long register, so i wonder that how to solve this kind of problem.
 
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