BJT diff amp in question here
In the diff mode it is true that ib1 = -ib2
For the common mode i was always under the impression that ib1 = ib2
Both inputs are the same v1 = v2 = vin
Hence the current out of the emitter is the sum of ib1 and ib2 going to an RE resistor.
Is this not true?
In the diff mode it is true that ib1 = -ib2
For the common mode i was always under the impression that ib1 = ib2
Both inputs are the same v1 = v2 = vin
Hence the current out of the emitter is the sum of ib1 and ib2 going to an RE resistor.
Is this not true?