Delta to Wye Conversion

ewr

Joined Oct 2, 2016
7
Hi,

Please refer to the Delta and Wye network diagrams here, https://www.allaboutcircuits.com/textbook/direct-current/chpt-10/delta-y-and-y-conversions/

In Delta to Wye conversion, we obtain the resistance for the Wye network from node A to node B as R(AB) = R_A + R_B. But from my understanding R_A and R_B would not be connected in series since the middle node is also connected to R_C. So why are we allowed to obtain R(AB) = R_A + R_B?

Maybe I need clarification of what a series circuit is.

Thank you for the help.

shteii01

Joined Feb 19, 2010
4,644
You are doing it wrong.

WBahn

Joined Mar 31, 2012
26,398
Hi,

Please refer to the Delta and Wye network diagrams here, https://www.allaboutcircuits.com/textbook/direct-current/chpt-10/delta-y-and-y-conversions/

In Delta to Wye conversion, we obtain the resistance for the Wye network from node A to node B as R(AB) = R_A + R_B. But from my understanding R_A and R_B would not be connected in series since the middle node is also connected to R_C. So why are we allowed to obtain R(AB) = R_A + R_B?

Maybe I need clarification of what a series circuit is.

Thank you for the help.
See the following, which should explain the whats and whys about the conversions.