Delta to Wye Conversion

Thread Starter

ewr

Joined Oct 2, 2016
7
Hi,

Please refer to the Delta and Wye network diagrams here, https://www.allaboutcircuits.com/textbook/direct-current/chpt-10/delta-y-and-y-conversions/

In Delta to Wye conversion, we obtain the resistance for the Wye network from node A to node B as R(AB) = R_A + R_B. But from my understanding R_A and R_B would not be connected in series since the middle node is also connected to R_C. So why are we allowed to obtain R(AB) = R_A + R_B?

Maybe I need clarification of what a series circuit is.

Thank you for the help.
 

WBahn

Joined Mar 31, 2012
26,398
Hi,

Please refer to the Delta and Wye network diagrams here, https://www.allaboutcircuits.com/textbook/direct-current/chpt-10/delta-y-and-y-conversions/

In Delta to Wye conversion, we obtain the resistance for the Wye network from node A to node B as R(AB) = R_A + R_B. But from my understanding R_A and R_B would not be connected in series since the middle node is also connected to R_C. So why are we allowed to obtain R(AB) = R_A + R_B?

Maybe I need clarification of what a series circuit is.

Thank you for the help.
See the following, which should explain the whats and whys about the conversions.

https://www.allaboutcircuits.com/technical-articles/delta-wye-transforms-behind-the-scenes/
 
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