In a DAC practical circuit I read the 'step' change in Vout can be given as:
Vstep = Vref/2^n
where n is the number of bits in the digital word.
Eg.
Vref = 5V
n = 8-bits
5V/256 = 19.5mV
41(decimal) x 19.5mV = 800mV.
Is it OK to use this same procedure for ADC successive approximation circuit calculations?
Eg.
Vsig = 3.6V
8-bit, 5V ADC
5V/256 = 19.5mV
Vsig/19.5mV = 183(decimal)
Vstep = Vref/2^n
where n is the number of bits in the digital word.
Eg.
Vref = 5V
n = 8-bits
5V/256 = 19.5mV
41(decimal) x 19.5mV = 800mV.
Is it OK to use this same procedure for ADC successive approximation circuit calculations?
Eg.
Vsig = 3.6V
8-bit, 5V ADC
5V/256 = 19.5mV
Vsig/19.5mV = 183(decimal)