How do you calculate for coupling capacitors for common emitter multistage amplifiers? And what does the input impedance of the common emitter amplifiers have to do with it?

 

How do you calculate for coupling capacitors for common emitter multistage amplifiers? And what does the input impedance of the common emitter amplifiers have to do with it?

The purpose of an inter-stage coupling capacitor is to block DC from reaching the input of the following stage.
It constitutes a high-pass filter, i.e. low frequencies are attenuated.

What you need to determine is the low frequency cut-off point you are willing to accept. Look up RC high-pass filter to determine the cut-off frequency. When in doubt, you can go with higher capacitance rather than lower capacitance.

 

a too large coupling capacitor may induce temporal clipping or a very-low frequency "square wave" excursion of the output
especially at frequency jump points so it is better to keep as low as possible for wideband signal

 

a too large coupling capacitor may induce temporal clipping or a very-low frequency "square wave" excursion of the output
especially at frequency jump points so it is better to keep as low as possible for wideband signal

Sorry, I don't understand any of that.

What generates this very-low frequency "square-wave"?
What are "frequency jump points"?

 

How do you calculate for coupling capacitors for common emitter multistage amplifiers? And what does the input impedance of the common emitter amplifiers have to do with it?

The lower cutoff frequency wo for the highpass (start of the passband) is determined by the coupling capacitor Cs and the corresponding resistor Reff which is responsible for charging/discharging of Cs.
The effective time constant is T=Reff*Cs with wo=1/T
This resistor Reff involves the internal resistance of the driving signal source Ro as well as the input resistance of the amplifying device rin (dynamic quantity)