Remove the ground symbols and you are okay.Like this.
Remove the ground symbols and you are okay.Like this.
You have to redraw the circuit and connected the first ground together and labels as GND1, and the first output labels as V1 or Vo1, the second ground labels as GND2, and the second output labels as V2 or Vo2, the third ground labels as GND3, and the third output as V3 or Vo3, of course you can't connected all the ground together.Like this.
Below is the LTspice simulation my take on using an optocoupler to control two (or more) LM317's from one voltage control.I'm still thinking of trying something with an optocoupler... I have a bunch of these,
and maybe I can learn something new with them.
Below is the LTspice simulation my take on using an optocoupler to control two (or more) LM317's from one voltage control.
The control voltage could be generated from a pot of course.
The op amp drive for the optos provides a voltage to current conversion by putting the input diodes in the feedback loop to avoid the non-linearity of the LED input voltage versus current.
The pots (U6 and U7) are to allow matching of the two outputs due to variations between LM317s and the opto gains.
It shows one supply with common grounds, which you would need to separate for your application.
View attachment 114872
The 4N28 has lower transfer gain than the 4N25, so the value of R1 has to be reduced to increase the LED current for the same output current.
Below is the circuit with 4N28's.
I also added a 2.5V reference voltage and a pot for the voltage control.
View attachment 114887
The voltage at the junction of R2 and the top of the pot is 2.5V from the U9 shunt voltage reference............
What is the voltage at the terminal of R2 and the Op Amp?
Is there a 100 ohm resistor on the wiper of the 10k pot? Sorry, I'm a little
soft on nomenclature/spice.
The op amp will compensate for any input diode voltage change with temperature but not for any change in the input/output gain.Will temperature fluctuation of the optocoupler cause any problems, or will the op amp compensate?
The voltage at the junction of R2 and the top of the pot is 2.5V from the U9 shunt voltage reference.
The opamp input voltage varies between 0V and 2.5V as determined by the wiper position.
No, there is no 100 ohm resistor. It's just a 10kΩ pot.
The w/100 is the wiper position (0 to 1 equals 0% to 100% wiper rotation) for simulation purposes.
The op amp will compensate for any input diode voltage change with temperature but not for any change in the input/output gain.
As shown all V+ are the same voltage, generated by V1 (arbitrarily 25V).
If you use a separate voltage for the op amp and reference then it should be at least 12V.
I tried several potentiometer values for U8, from1k to 47k, and they all worked the same:The 4N28 has lower transfer gain than the 4N25, so the value of R1 has to be reduced to increase the LED current for the same output current.
Below is the circuit with 4N28's.
I also added a 2.5V reference voltage and a pot for the voltage control.
View attachment 114887
use a set of gears on N independent pots?is there some other way I can do this?
As long as the digital pots are optically coupled for isolation.Or a mcu reading off one pot and controls N independent digital pots?
by Jake Hertz
by Jake Hertz
by Jake Hertz