Dear members,
When you have a clipper circuit with two diodes in serie to the power supply. I try to draw it. The two diodes are with the cathode to the Vs+
Vs +
|
|
|
diode
|
|
|
|
diode
|
|
|
GND
This circuit will clip the voltage, depend on what is the power supply value. for instance, a Vs from 5V, then the upper diode wil clip at 5.7V and the lower at -5.7.
But how can the lower diode clips the negative voltage to -5.7. The anode is alaways 0V, thus you must conduct at -0.7V.
Can somebody explain me that
Thank you,
Jef
When you have a clipper circuit with two diodes in serie to the power supply. I try to draw it. The two diodes are with the cathode to the Vs+
Vs +
|
|
|
diode
|
|
|
|
diode
|
|
|
GND
This circuit will clip the voltage, depend on what is the power supply value. for instance, a Vs from 5V, then the upper diode wil clip at 5.7V and the lower at -5.7.
But how can the lower diode clips the negative voltage to -5.7. The anode is alaways 0V, thus you must conduct at -0.7V.
Can somebody explain me that
Thank you,
Jef