How ?? This is wrong see my additional note.Thanks for the help. I came up with 200mV.
No. It is a trick question. Google Wheatstone Bridge.Thanks for the help. I came up with 200mV.
Yep, (R5 + R6) are connected in parallel with (R3+R4). As I says early please notice that this two voltage divider (R3,R4) and (R5,R6) are the same. They have the same voltage ratio R4/(R3+R4) = R6/(R5+R6).Here are my calculations. Would you mind showing me where I went wrong?
Just remember that Vxy is short for Vx - Vy.This is an extra credit question from my homework. Can someone spot a trick here or anything? My instructor likes to throw curveballs at us sometimes. How do I go about finding the voltage from A to B? View attachment 103474
In this particular case, if you look at the values closely, you can answer the question by inspection. But, if not, just analyze the circuit as described above and you will get the answer. Once you do, then ask yourself if, in hindsight, there are things you could have spotted that would have led you to the same result with less work.Just remember that Vxy is short for Vx - Vy.
So find the voltage at Node A (Va), Find the voltage at Node B (Vb). Then compute Vab = Va - Vb.
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by Jake Hertz
by Jake Hertz
by Jake Hertz