The difference is negligible. But the load voltage remains nearly same whether we apply a 200V or a 600V.
Attachments
-
109.7 KB Views: 9
yes, but as soon as he places the other end of the resistor to capacitive divider (which we hope won't blow) the lower one comes active ...the lower half of the circuit is redundant.
IMHO there is no point in continuing with the design configured in this way.
↑ Please do yourself a favour and plot the current through R7 () . . .Which means the lower half of the circuit is redundant.
sorry i missed / forgot that - you have already conducted a simple setup testI was able to drive the mosfet alone (in boost converter circuit)
↑↑ if the upper leg of the bridge is closed the voltage would be near zero at R7 even without the lower leg (i hate principial unexplained schematics) -- the author (most probably assumed some active load Z there . . . and ?for noting? that the other end has an electrical ~AC --and/or-- DC pathway to GND drawed the connection . . .) e.g. ← it definitely is an "expected result" but a very very very ... (turn the page)This is my expected result.
by Aaron Carman
by Lianne Frith