I should have stated my question better. I think I'm getting thrown off by the capacitors in the circuit. What exactly constitutes "low-frequency". When creating my equivalent circuit, I've tried converting Ce to a resistance value.The Hybrid-pi model is a three-terminal subcircuit that goes in place of the transistor. Your DC supplies get turned off, and low-frequency capacitors are replaced with shorts.
You need to show your best attempt from here.
Uh... no.Shouldn't the DC component become the magnitude of the of the AC sinusoidal signal?
The voltage is always going to oscillate about the DC value -- what other option is there?Well what about using the DC component as the magnitude of the AC sinusoidal. The voltage would oscillate about the DC value.
No, Re has both a DC and an AC current going through it. The load only has an AC signal in it because the DC signal is blocked.So the only voltage going through Re is the AC input signal? Does that mean Vre = Vrl because they're both in parallel?
|Thread starter||Similar threads||Forum||Replies||Date|
|M||Calculating Power Dissipation - What I need for a power supply||Digital Design||7|
|L||Calculating power consumption||General Science, Physics & Math||8|
|G||Calculating the RF coverage area for LTE networks and benefits of higher power eNB||Wireless & RF Design||6|
|When calculating LED power consumption, how precise must one be for selecting power supply values?||General Electronics Chat||25|
|C||Calculating Power Dissipated in Sources||Homework Help||9|
|Calculating Power Dissipation - What I need for a power supply|
|Calculating power consumption|
|Calculating the RF coverage area for LTE networks and benefits of higher power eNB|
|When calculating LED power consumption, how precise must one be for selecting power supply values?|
|Calculating Power Dissipated in Sources|
by Jake Hertz