Can someone tell me what is output voltage for this scheme?
Attachments
-
5.4 KB Views: 16
What is the voltage drop of a diode? What will it do on the negative half cycle of the input?No this is part of bigger scheme, I think it should be around 5V
How are you coming up with 5V for the output?The output voltage should activate the optocoupler
Then as AK said, the output will be a half wave rectified sinewave and the voltage won't be 5V (DC or AC). You need to add reverse polarity protection for the opto LED.Its not homework
You're welcome.Thank you for answer
Not enough current to turn on the optocoupler?The output voltage should activate the optocoupler
The measured voltage output was 0.5V but the optocoupler didn't activate, so I think it should be around 5V for it to work
To get the 20 mA or so the optocoupler needs you need about 11,000 ohms, but that would mean you have to be a 10 Watt resistor. The voltage across the LED sets itself. (Maybe 1.2 V?) And yes, use a protection diode.Can someone tell me what is output voltage for this scheme?