So I am designing my own midi to CV converter. my design is similar to the one below, and will be connected to a sawtooth oscillator. My design is basic and will only require a range of 5 octaves, highest being just over 2000Hz. Therefore from my knowledge my cut off frequency will not need to be much more than that.
However, taking the below circuit as an example , lets say that it is designed to output the highest human range of 20,000Hz! Using the equation:
R = 6k8 & C = 270p
Which calculates cut-off frequency to be 86685 Hz!! why is it so high? There are a few designs that produce similar results online too. Am i missing something? Do i need to factor something else into the equation?
However, taking the below circuit as an example , lets say that it is designed to output the highest human range of 20,000Hz! Using the equation:
R = 6k8 & C = 270p
Which calculates cut-off frequency to be 86685 Hz!! why is it so high? There are a few designs that produce similar results online too. Am i missing something? Do i need to factor something else into the equation?