OK so maybe I'm just an idiot but I have a question regarding the following problem.

(x || y || !z) & (!x || !y || z)

Now am I getting this incorrect by assuming that that reduces down to just true? It doesn't seem to work out so any help would be appreciated.

 

snowrei,

Why don't you post your problems with notation like this. (x+y+z')(x'+y'+z) ?

Now am I getting this incorrect by assuming that that reduces down to just true?

What is your question? What is your input?

It doesn't seem to work out so any help would be appreciated.

Restate your problem more clearly.

Ratch

 

Sorry, I'm trying to reduce the equation down to a minimal form, and if I'm reading the distributive property properly, I can reduce (x+y+z')(x'+y'+z) to xx'+yy'+z'z which reduces to 1.

I don't think that's correct and I'm trying to find the error in my logic.

 

...if I'm reading the distributive property properly, I can reduce (x+y+z')(x'+y'+z) to xx'+yy'+z'z which reduces to 1.

I don't think that's correct and I'm trying to find the error in my logic.

xx'+yy'+z'z reduces to zero, not one.

Also, I think you have misunderstood the distributive property. You need to distribute each term in (x+y+z') to each term in (x'+y'+z).