hi, im stuck with this boolean algebra.

F = (X + Y + X . Z) . (Y +X')

btw: the law A + AB = A
so does A + AB' = A?

thanks in advance

 

yes, A+AB'=A----> its telling you it does not matter what b' is

change order so you can see the form A+AB

F=(X+XZ+Y) (Y+X')
=[(X+XZ)+Y] (Y=X')

X+XZ =======> A+AB

=(X+Y)(Y+X')

Then could multiply out and use:
XX'=0
YY=Y
and look for the form A+AB=A again

 

A + AB = A.(1+B) = A.1 = A

A + AB' = A.(1+B') = A.1 = A

Anything in OR operation with 1 results 1...

Your Ques. Ans . = Y