https://imgur.com/a/sDrv0
I do not understand how the part of the transfer function associated with the constant magnitude offset is calculated. Looking at the farmost left side of the plot, it has a slope of -20db/decade, meaning that the graph intersects the x-axis at 40w if you ignore all poles except for 1/s. This means that, in order to calculate the constant magnitude offset, you have to figure out how much of a gain would put the intersection back at 1w, the place where a pole of 1/s would have put it.
Don't you need a magnitude offset of 39db to set the intersection back at 1w? That means that the value of K is equal to the solution of the equation 20log(x) = 39. Can someone explain where my reasoning is wrong?
I do not understand how the part of the transfer function associated with the constant magnitude offset is calculated. Looking at the farmost left side of the plot, it has a slope of -20db/decade, meaning that the graph intersects the x-axis at 40w if you ignore all poles except for 1/s. This means that, in order to calculate the constant magnitude offset, you have to figure out how much of a gain would put the intersection back at 1w, the place where a pole of 1/s would have put it.
Don't you need a magnitude offset of 39db to set the intersection back at 1w? That means that the value of K is equal to the solution of the equation 20log(x) = 39. Can someone explain where my reasoning is wrong?