Good morning all,
At first, I'm not so good in the English language so excuus me for that.
My Question:
I want to test 2 serie battery's (12V+12V=) 24V 7Ah (C20 test) lead acid VLRA type.
They are used to power a motor (24VDC, maxload = 40ADC) (maxload only occurs only for a few seconds (20-30sec)).
After doing this they will be recharged.
How could I test these battery's ?
I want to know how the behave.
What do I want to accomplish is:
A emplacement of a battery connectect to a Resistive Loadbank (to simulate the motor) and I want to read de battery by checking the voltage with an ADC (microcontroller) and send this to a PC for analysing.
What I thought so far:
A lead acid battery cannot read out correctly when there is an load attached to this battery, so I want to try to switch off the load and then read it out.
The resistive loadbank is not a complete simulation of a motor but would it be enough?
P = U*I = 24VDC * 40ADC = 960Watt, so i need to dissipate a lot of heat.
If I want to withdraw 40A out of the battery I need to use a 0.6ohm 1kW resistor (or a lot of resistors in parallel), but when the load is attached to the battery, the OCV (Open Circuit Voltage) drops, so I won't withdraw 40A from the battery anymore. how to solve?
I've checked these topic's:
Electronic Loads A constant current withdraw.
Power MOSFET is core of regulated-dc electronic load
Points:
1) How to withdraw 40A from a lead acid battery (for only a few seconds 20 -30 sec)
2) How to read the lead acid battery out correctly.
3) The resistive loadbank is not a complete simulation of a motor but would it be enough?
4) How to withdraw a constant current from a lead acid battery?
Any thoughts, comments and help would be greatly appreciated.
Greets,
Leek1001.
At first, I'm not so good in the English language so excuus me for that.
My Question:
I want to test 2 serie battery's (12V+12V=) 24V 7Ah (C20 test) lead acid VLRA type.
They are used to power a motor (24VDC, maxload = 40ADC) (maxload only occurs only for a few seconds (20-30sec)).
After doing this they will be recharged.
How could I test these battery's ?
I want to know how the behave.
What do I want to accomplish is:
A emplacement of a battery connectect to a Resistive Loadbank (to simulate the motor) and I want to read de battery by checking the voltage with an ADC (microcontroller) and send this to a PC for analysing.
What I thought so far:
A lead acid battery cannot read out correctly when there is an load attached to this battery, so I want to try to switch off the load and then read it out.
The resistive loadbank is not a complete simulation of a motor but would it be enough?
P = U*I = 24VDC * 40ADC = 960Watt, so i need to dissipate a lot of heat.
If I want to withdraw 40A out of the battery I need to use a 0.6ohm 1kW resistor (or a lot of resistors in parallel), but when the load is attached to the battery, the OCV (Open Circuit Voltage) drops, so I won't withdraw 40A from the battery anymore. how to solve?
I've checked these topic's:
Electronic Loads A constant current withdraw.
Power MOSFET is core of regulated-dc electronic load
Points:
1) How to withdraw 40A from a lead acid battery (for only a few seconds 20 -30 sec)
2) How to read the lead acid battery out correctly.
3) The resistive loadbank is not a complete simulation of a motor but would it be enough?
4) How to withdraw a constant current from a lead acid battery?
Any thoughts, comments and help would be greatly appreciated.
Greets,
Leek1001.