Hello,

I'm trying to work on a circuit that can switch the LED on or off depending on the state of the MOSFET in the circuit. To make things a little bit more clear, I will attach the circuit that I'm working on. There is a BJT transistor connected to a solar cell. The solar cell will make the BJT either open, or as a short line switch. In case the BJT is open, the MOSFET will be on, and the LED will lighten up. Otherwise, the LED will remain off.

I have simulated the circuit and it seems like it works just fine! But my question is, the 10k ohm resistor in the circuit I simulated does not seem to have a voltage drop across it. It kinda acts like it's not there. Any idea what could be the problem here?

The project that I'm working on is the same as the one in this video:

 

If Q1 is off, there will be no drop across R1 since there is no current through it.
It only has voltage across it when Q1 is on.

 

If Q1 is off, there will be drop across R1 since there is no current through it.
It only has voltage across it when Q1 is on.

Now it makes sense, thank you!