Hello,
According to this link, http://www.allaboutcircuits.com/textbook/semiconductors/chpt1/attenuators/, I'm curious in the equation PI = VI II = (VI )^2 / R
Since, after plugging an attenuator in, the VI does not lie across an input resistance directly, so the II is not VI/R, which will contradict the equation above.
If I don't make this clear, please look at the attached picture or inform me on this thread.
Thank you
BlackMelon
According to this link, http://www.allaboutcircuits.com/textbook/semiconductors/chpt1/attenuators/, I'm curious in the equation PI = VI II = (VI )^2 / R
Since, after plugging an attenuator in, the VI does not lie across an input resistance directly, so the II is not VI/R, which will contradict the equation above.
If I don't make this clear, please look at the attached picture or inform me on this thread.
Thank you
BlackMelon
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