The zener diode is depicted in its SOT23 packaging with the spare not connected terminal.Impossible to say with so little information.
For starters, what is the rail at the top of the diagram connected to, and what is the coloured box surrounding D5?
Ahhhhh, damm old fool never thought that the rail would be negitavly biased. Oh boy am I getting old.On the positive half-cycle of the supply, the diode wil be reverse biased so no current will flow and there will be no voltage across the zener.
On the negative half-cycle the diode will be forward biased and will conduct the supply voltage to the zener. The zener diode will be reverse biased and will conduct when the voltage across it reaches 7.5V. The two diodes will conduct and above about 8.5V will conduct as much current as the supply is capable of - there is no resistor to limit the current. So if the supply is capable of a large current then both diodes would be destroyed.
If there is nothing else connected to the junction of the two diodes then I can see no useful purpose for this arrangement. Did you invent this circuit or did you see it printed somewhere?
There is a 'conversation' facility on AAC but it would be better for any discussions to be on the forum. I have only one little brain with knowledge of a few areas, the forum has many brains with knowledge over a much wider range of topics.Is there a way to PM you?
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