Hey guys,
I am having some problems making the correct assumptions involving an inverting amplifier (attached)...
Assumptions:
I1 = I2
V- = 0
I1 = C1 (dVin/dt)
I2 = C2 (-dVout/dt)
Question: Prove Vout = -Vin(C1/C2)
I have arrived at this solution, but I am not sure I did it the right way or I got my assumptions right by coincidence - specifically for I2. Even then, I may have jumped a step which seems a bit dodgy to me now...
Since I1 = I2,
C1(dVin/dt) = C2(-dVout/dt)
C1(dVin) = C2(-dVout)
dVout = -dVin(C1/C2)
therefore Vout = -Vin(C1/C2)
Could somebody tell me whether I did this correctly? For some reason I feel I am not allowed to get rid of the 'd' that easily...
Thank you
I am having some problems making the correct assumptions involving an inverting amplifier (attached)...
Assumptions:
I1 = I2
V- = 0
I1 = C1 (dVin/dt)
I2 = C2 (-dVout/dt)
Question: Prove Vout = -Vin(C1/C2)
I have arrived at this solution, but I am not sure I did it the right way or I got my assumptions right by coincidence - specifically for I2. Even then, I may have jumped a step which seems a bit dodgy to me now...
Since I1 = I2,
C1(dVin/dt) = C2(-dVout/dt)
C1(dVin) = C2(-dVout)
dVout = -dVin(C1/C2)
therefore Vout = -Vin(C1/C2)
Could somebody tell me whether I did this correctly? For some reason I feel I am not allowed to get rid of the 'd' that easily...
Thank you
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