My professor asked me to also find the voltage drop V2(t) across the middle section using voltage divider (it's a section consists 30ohm in parallel to the 5mF capacitor).
I found V(t) across current source, but I don't get the point of using voltage divider to get V2(t). Can't I just use the current going through the middle section and use ohm's law to find V2(t)?

The equation for v2 is

10angle45°(30+(-j/ωC)) but I didn't use voltage divider to find it.

Could anyone explain me why I have to use voltage divider to get V2(t)?

I apologize for putting "a" in the title. I couldn't post this thing because of the title so I put some random letter.

 

Whatever image you tried to embed isn't showing up. Please upload the image as an attachment to your post.

 

And next time use a descriptive title. Don't ever post useless titles (i.e. one letter, or "need help!" or "urgent!"). Those types of titles are to be avoided at all times.

 

In his defense, he apparently tried posting with a more descriptive title and ran into our notorious title-length issue. So he went to the opposite extreme.

I seem to recall that titles less than 20 characters seldom cause problems.

 

In his defense, he apparently tried posting with a more descriptive title and ran into our notorious title-length issue. So we went to the opposite extreme.

I seem to recall that titles less than 20 characters seldom cause problems.

If that's the case I apologize for being rude, but you can still post a descriptive title that doesn't turn up a blank page.

 

looks weird.... I just right clicked the image and opened in the new tab and it worked.

 

looks weird.... I just right clicked the image and opened in the new tab and it worked.

You didn't post a link to the image, that's why....

Here is the image:

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My professor asked me to also find the voltage drop V2(t) across the middle section using voltage divider (it's a section consists 30ohm in parallel to the 5mF capacitor).
I found V(t) across current source, but I don't get the point of using voltage divider to get V2(t). Can't I just use the current going through the middle section and use ohm's law to find V2(t)?

The equation for v2 is

10angle45°(30+(-j/ωC)) but I didn't use voltage divider to find it.

Could anyone explain me why I have to use voltage divider to get V2(t)?

I apologize for putting "a" in the title. I couldn't post this thing because of the title so I put some random letter.

Okay, now that we can see the circuit we can take a shot at answer your question.

First, note that if you use the voltage divider approach you never need to determine the current in the circuit at all. But, having gone ahead and found the current, then yes, the easiest approach from that point to finding the voltage across the middle section is to use Ohm's law for impedances.

But that's not the way you were told to do it. The bottom line is that the reason you have to use the voltage divider approach is because that is the approach you were instructed to use. Keep in mind that most circuit analysis problems can be solved using a variety of techniques. The only way to ensure that you learn each technique is to require you to use that specific technique.

An effective way to get you to start developing the skills of determining when to use each method is to have you analyze the same circuit multiple times using a different method each time. So imagine what the answer would be to someone that asked why they need to analyze the circuit again when they've already found the answer some other way.