470 Ohm resistor burnt between triac and optoisolator

Tonyr1084

Joined Sep 24, 2015
9,744
Sorry. PFA hand-drawn schematic of the circuit. The resistor in the black box was burned.View attachment 225830
Referenced? Yes. Defined? Nope. For all we know the TS could be using two 47Ω resistors to create a 50% voltage divider. Or maybe two 1MΩ resistors, still creating a 50% voltage divider. Two stupidly extreme possibilities, given that the TS wants to run some AC fans which we also know nothing about. Voltage dividers are not going to work to run a fan.
 

Thread Starter

ssd_9

Joined Sep 2, 2020
17
... From the MOC3043 datasheet, it may be that the emitter led is not being activated correctly, and that the internal triac is not being turned on. The datasheet example circuit shows the led anode, pin #1, being held high, using an appropriate current limiting resistor (5 ma.), with a turn on signal, pin #2, being brought low as required.
... Could this be related to the burned resistor problem?
... Also, there should be a 330 Ω resistor between pin#4 and the external triac gate ... refer to the datasheet for the correct external wiring arrangement. If the load is highly inductive, a parallel! snubber branch may fix any problem ... per datasheet example circuit.
... Edit ... The forward biased led diode current should only be 5 ma., not the 30 ma. stated previously, as per datasheet specifications.
Thanks. This worked for me. Now everything is working fine.
 

Thread Starter

ssd_9

Joined Sep 2, 2020
17
Couple questions: First, what is pin 2 connected to? The LED inside isn't going to turn ON unless it's pulled to ground somehow. And are you sure you want a zero crossing detector? Second is the BTA136; what is it? And why are pins 1 & 3 shorted? Third, what is your AC voltage? Fourth, what kind of voltage divider? What are the resistor values on the voltage divider? You could simply be drawing too much current through your circuit.

Just because someone on YouTube said to use a 470Ω resistor - that doesn't mean anything without knowing the voltage being applied. IF your AC voltage is 120VAC and you use a 470Ω resistor that would assume an amperage of 255mA. At that amperage your resistor needs to handle 30.6 watts (not milliwatts). Yeah, every resistor in that circuit will burn up. But I see you also have a 180Ω resistor in series before the (shorted) BTA136 Even if you include the 180 in series with the 470, that's still 184mA @120VAC = 22 watts. A quarter watt resistor should light up like a light bulb. Albeit very briefly.

View attachment 225855 View attachment 225857
Thank you. I had corrected my circuit according to the datasheet of MOC3043 and now everything is working.
 
Top