The right motor you posted that it seems has gear in it, you can turn around two motors, if the right one isn't that smoothly as left one then it should be has the gear.
The file size was too big, before you attach it remember to compress it to a appropriate file size next time, and the new circuit need to adding a Rbe for Q2, and adding another resistor Rc1 for the Vc1 of first transistor, the Rc1 should be connected to Vcc from Vc1 and it can be as:
1. Vcc=12V, Motor = 600mA/Ib1 = 600mA/10 = 60mA
Rc1=(Vcc-Vce1-Vbe2)/
Rc1= (12V-0.2V-0.9V)/60mA = 185 Ω,choose 180 Ω or 150 Ω
2. Vcc=12V, Motor = 500mA/Ib1 = 500mA/10 = 50mA
Rc1=(Vcc-Vce1-Vbe2)/
Rc1= (12V-0.2V-0.9V)/500mA = 222 Ω, choose 220 Ω or 200Ω
You should choose the Ic current of Q2 have 5 times of the required current as iC=600 mA then it should be Ic =3A.
And the Ic1 of Q1 = 60mA * 5 = 300mA.
So Q2_Ic2 = 3A or more.
Q1_Ic1 = 300 mA or more.
The circuit will be as below:
The file size was too big, before you attach it remember to compress it to a appropriate file size next time, and the new circuit need to adding a Rbe for Q2, and adding another resistor Rc1 for the Vc1 of first transistor, the Rc1 should be connected to Vcc from Vc1 and it can be as:
1. Vcc=12V, Motor = 600mA/Ib1 = 600mA/10 = 60mA
Rc1=(Vcc-Vce1-Vbe2)/
Rc1= (12V-0.2V-0.9V)/60mA = 185 Ω,choose 180 Ω or 150 Ω
2. Vcc=12V, Motor = 500mA/Ib1 = 500mA/10 = 50mA
Rc1=(Vcc-Vce1-Vbe2)/
Rc1= (12V-0.2V-0.9V)/500mA = 222 Ω, choose 220 Ω or 200Ω
You should choose the Ic current of Q2 have 5 times of the required current as iC=600 mA then it should be Ic =3A.
And the Ic1 of Q1 = 60mA * 5 = 300mA.
So Q2_Ic2 = 3A or more.
Q1_Ic1 = 300 mA or more.
The circuit will be as below: