I was doing general source transformation problems (like in this thread http://forum.allaboutcircuits.com/showthread.php?t=60736). The kind of problem where you have a large circuit and successfully transform voltage sources in series with a resistor to a current source in parallel with the same resistor... and vice-versa... all the way down to a single voltage source in series with a resistor or a current source in parallel with the same resistor. The final circuit would then be equivalent with respect to two terminals a and b at the far right of the circuit. At this point I had not studied Thevenin/Norton.
I then learned about Thevenin / Norton and began working some problems and then I realized that Thevenin / Norton isn't much more than the previous general transformation problems I was doing previously (am I right?). For example, when I did general transformations as described in the first part and ended up with only a voltage source in series with a resistor, then this is exactly the Thevenin circuit... (same with Norton and the current source parallel to resistor case)... Am I right?
It seems to me that Thevenin/Norton is the very same general transformation and simplification I was already doing in the first place... Am I right?
Say for example I begin with a large circuit and simplify it down to a single voltage source in series with a resistor at the left of terminals a and b.... This would be exactly the Thevenin circuit... All Thevenin/Norton do is giving "alternative" methods to find the same equivalent circuit (which I am not even sure it is easier... in this case, what really is the use of Thevenin/Norton?)
I just want to make sure Im understanding correctly
Thank you
I then learned about Thevenin / Norton and began working some problems and then I realized that Thevenin / Norton isn't much more than the previous general transformation problems I was doing previously (am I right?). For example, when I did general transformations as described in the first part and ended up with only a voltage source in series with a resistor, then this is exactly the Thevenin circuit... (same with Norton and the current source parallel to resistor case)... Am I right?
It seems to me that Thevenin/Norton is the very same general transformation and simplification I was already doing in the first place... Am I right?
Say for example I begin with a large circuit and simplify it down to a single voltage source in series with a resistor at the left of terminals a and b.... This would be exactly the Thevenin circuit... All Thevenin/Norton do is giving "alternative" methods to find the same equivalent circuit (which I am not even sure it is easier... in this case, what really is the use of Thevenin/Norton?)
I just want to make sure Im understanding correctly
Thank you