Very simple C syntax question

[indianhits]

both are same even if you put curly brackets or not

[count_volta]

Originally Posted by mik3

int find is a subroutine and the return instruction ends the subroutine. Thus, it will not execute the return -1 if a[i]==x.

Okay I see, so if a[i] == x, it will return i and go back to main program, but if a[i] never equals to x, it will get to the end of the loop, jump out of the loop and return -1 and then go back to main program.

Cool thanks. Now I can do that in mips assembly pretty easily.

[Harrington]

Hi this should give you a better idea of how this works

I've rewritten the code for you so that it makes more sense then you can see what it does and hopefully get a better understanding

#include <stdio.h>


// declare global functions

int find( int a[], int n, int x) ;

int Array[] = { 1,3,5,4,10} ;


// define the function in full here


int find( int a[], int n, int x)
{
int i = -1 ;

for (i=0; i!=n; i++)
{

if(a[i]==x){

printf("Match found %d at index X = %d \n \n ",i,x);

return i;


} // end if

}// end for


if (i == -1 )
{
printf("\n No Match found \n") ;

}

return i;



}// end function






void main()
{


char ch =' ';

int x = 0;

int n = 0 ;

int match = 0 ;

int j = 0 ;

int flag = 1 ;


printf("Enter q to quit or r to run \n\n");


while(flag ==1){


ch = getchar(); // get user input


if(ch == 'r')
{
printf(" Enter a value for x please followed by enter\n ") ; // prompt the user for input

scanf ("%d",&n);

printf("Enter a value for n please in the range of 0 to 5 followed by return\n");

scanf ("%d",&x); // get user input

match = find(Array,n,x); // simply return our value here



printf("\n Array contents were \n");
for( j = 0 ; j < 5 ; j ++)

{

printf(" %d " ,Array[j]);
}




printf("\n\n q to quit or r to run\n\n");

}

if (ch =='q')
{

flag = 0 ;

}



} // end while


printf("\n User typed q \n **** Quitting program **** \n" );




}// end main method