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Greetings,
given a laser beam of 0.5 mm in diameter, hitting a light sensitive target at 10 meters which will register a pulse as small as 1 uSec, what would the differential equation (*) for the number of times per second the beam will be cut during a normal rainstorm?
*) I assume it would be a diff.eq, but am near clueless how to approach this.
"Raindrops range from 1/100 inch (.0254 centimeter) to 1/4 inch (.635 centimeter) in diameter... Not including wind-driven rain, raindrops fall between 7 and 18 miles per hour (3 and 8 meters per second) in still air. The range in speed depends on the the size of the raindrop. Air friction breaks up raindrops when they exceed 18 miles per hour. "
thanks much for any suggestions,
Howard
________________________________
references:
http://www.weatherwizkids.com/Rain.htm
http://ga.water.usgs.gov/edu/raindropshape.html
given a laser beam of 0.5 mm in diameter, hitting a light sensitive target at 10 meters which will register a pulse as small as 1 uSec, what would the differential equation (*) for the number of times per second the beam will be cut during a normal rainstorm?
*) I assume it would be a diff.eq, but am near clueless how to approach this.
"Raindrops range from 1/100 inch (.0254 centimeter) to 1/4 inch (.635 centimeter) in diameter... Not including wind-driven rain, raindrops fall between 7 and 18 miles per hour (3 and 8 meters per second) in still air. The range in speed depends on the the size of the raindrop. Air friction breaks up raindrops when they exceed 18 miles per hour. "
thanks much for any suggestions,
Howard
________________________________
references:
http://www.weatherwizkids.com/Rain.htm
http://ga.water.usgs.gov/edu/raindropshape.html
