hi guy,

need help to explain about Z-transform basic. I am currenty study Digital Signal Processing (DSP), please view the attachment..it will make it clearer..thanks

 

Those values are the givens for the problem.

Each term is simply \(x(k)\delta(k-n)\) for a given k. So for x(-2), the term is \(x(-2)\delta(k-(-2)) = x(-2)\delta(k+2) = 1.5\delta(k+2)\), which is the first term in the answer.

You only have to write 6 terms because all of the others are given as zero.

 

I think you ve misunderstood a bit. Are you asking how x(-2)=1.5, x(-1)=0.5, and so on ?
If so, it is just an example function x(k) with a value of 1.5 and 0.5 at -2 and -1 respectively. And it is just substituted in the equation as Caveman has ponited out.

 

thanks for the help..^^ i really didnt see it..