# XC8 individuals bits configuration

Joined Dec 24, 2011
55
Dear friends
I found following individuals bit setting methods

Compiler XC8
MCU PIC18F

LATC6 = 1;
LATCbits.LATC6 = 1;

Both method final result is same

#### JohnInTX

Joined Jun 26, 2012
3,976
The first uses the bit variable type declaration of LATC and the second treats LATC as a structure with bitfields. Both methods are defined in <xc.h> and generate the same code :
From a disassembly listing:
Rich (BB code):
87:                LATC6=1;
7FC2  8C8B     BSF LATC, 6, ACCESS
88:                LATCbits.LATC6=0;
7FC4  9C8B     BCF LATC, 6, ACCESS
In the manual DS52053BP
Sec 5.4.2.1 BIT DATA TYPES AND VARIABLES describes the first construct and
Sec. 3.4.4.2 HOW CAN I ACCESS INDIVIDUAL BITS OF A VARIABLE and 5.4.4.2 BIT-FIELDS IN STRUCTURES describe the second one..

There may be times when you want to specify the port as a variable and use a pointer to the structure to select the port but for most IO, use the simpler one.

Last edited:

Joined Dec 24, 2011
55
Dear JohnInTX

Can I have more general info about " structure with bitfields"

Joined Dec 24, 2011
55
Hi

In the AVR following method is working
XMEGA
#define COMM_PORT PORTC
COMM_PORT.OUT =~((1<<LCD_E)|(1<<LCD_RW));

But in the PIC 18F XC8 does not support it

#### ErnieM

Joined Apr 24, 2011
8,019
Rich (BB code):
#define COMM_PORT PORTC
COMM_PORT.OUT =~((1<<LCD_E)|(1<<LCD_RW));
That is standard C, so the problem is not with XC8, the problem is something is undefined, either LCD_E, LCD_RW, or both.

Those definitions probably depend on how you wired in an LCD display.

Joined Dec 24, 2011
55
Hi
This code should be ON LED connected to the PORTD 0,1,2,3 bits but it only ON bit 0,1

Rich (BB code):
LATD  |= ( 1<<LATD0 | 1<<LATD1 | 1<<LATD2 | 1<<LATD3 );

Last edited:

#### ErnieM

Joined Apr 24, 2011
8,019
Again, it depends on how the symbols are defined. From your first post you know these are equivalent terms:

LATDC0 = 1;
LATDbits.LATD0 = 1;

So your expression could be rewritten as:

Rich (BB code):
LATD  |= ( 1<<LATDbits.LATD0 | 1<<LATDbits.LATD1 | 1<<LATDbits.LATD2 | 1<<LATDbits.LATD3 );
Now "1<<LATDbits.LATD0" has a value of either 1 or 2 depending on LATD0 being either 0 or 1. There is no way you can or together these values and get all 4 lower bits set.

The constant I believe you were looking for is named "_LATC_LATD0_POSN" in the device header file. I believe you could use the expression:

Rich (BB code):
LATD  |= ( 1<<_LATC_LATD0_POSN | 1<<_LATC_LATD1_POSN | 1<<_LATC_LATD2_POSN | 1<<_LATC_LATD3_POSN );
But it may be simpler to just say:

Rich (BB code):
LATD  |= 0x0F;