The Question States:
The switch is in position x for a long time before moving to position y at t=0.
Find the expression for V1(t) at t≥0.
My Answer:
First I found v0(t) using voltage divider. at t<0 where the capacitor is an open circuit.
Then at t>0 I used T= RC and did 1/T
Therefore:
vo(t) = vo(0)*e^t/T
Then I just said that vo(t) = v1(t) at t>o where the capacitor beneath the switch is now a short circuit because they are in parallel is that correct?
Thanks
The switch is in position x for a long time before moving to position y at t=0.
Find the expression for V1(t) at t≥0.
My Answer:
First I found v0(t) using voltage divider. at t<0 where the capacitor is an open circuit.
Then at t>0 I used T= RC and did 1/T
Therefore:
vo(t) = vo(0)*e^t/T
Then I just said that vo(t) = v1(t) at t>o where the capacitor beneath the switch is now a short circuit because they are in parallel is that correct?
Thanks
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