Hello everyone, I'm working on my first origional project and the goal is to put under glow on my longboard ( it's like a long skateboard) with LED strips, by my calculations the length of 12v LED strip i would need (60" [ 2 - 30" lengths]) would require .6 amps.
But my question is how can i drop the 18v of two 9v batteries down to 12v? or is there a better way to power them ( excluding 8 AA's theres not really room for that under my board) I'm a bit fuzzy on Ohm's Law but by my research it is Volts = amps * ohms? so i would need a 10Ω resistor? what else do i need to know? and am i even remotely correct?
In summary, im looking to power 60" of 12v LED strip with 2 9v batteries, is this an ok idea? and what resistor do i want? Or is this whole concept FUBAR?
But my question is how can i drop the 18v of two 9v batteries down to 12v? or is there a better way to power them ( excluding 8 AA's theres not really room for that under my board) I'm a bit fuzzy on Ohm's Law but by my research it is Volts = amps * ohms? so i would need a 10Ω resistor? what else do i need to know? and am i even remotely correct?
In summary, im looking to power 60" of 12v LED strip with 2 9v batteries, is this an ok idea? and what resistor do i want? Or is this whole concept FUBAR?