Let us say we have the following conditions with our op-amp:
Vcc = 0
Vee = 0
Vin = 1ms 5V pulse
Internal ESD protection diodes to each rail
Since my op-amp is unpowered, then the input signal is forward biasing the ESD diode from input to the positive power supply rail. Depending on the current from the signal source and perhaps the sinking ability of the positive power supply, wouldn't Vcc of the op-amp be connected to the Vin signal minus a diode drop thus providing power for a brief moment?
Vcc = 0
Vee = 0
Vin = 1ms 5V pulse
Internal ESD protection diodes to each rail
Since my op-amp is unpowered, then the input signal is forward biasing the ESD diode from input to the positive power supply rail. Depending on the current from the signal source and perhaps the sinking ability of the positive power supply, wouldn't Vcc of the op-amp be connected to the Vin signal minus a diode drop thus providing power for a brief moment?