# why is calculator giving in absolute form?

Discussion in 'Math' started by PG1995, Nov 20, 2011.

1. ### PG1995 Thread Starter Well-Known Member

Apr 15, 2011
813
6
Hi

Please have a look on the attachment. Could you please tell me why the calculator is giving the answer (arrow points to the answer under discussion) in absolute form? (x^2 - a^2)^2 would always be a +ve number by definition, so in my opinion there was no need to use absolute form. Please help me. Thanks.

Regards
PG

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2. ### Georacer Moderator

Nov 25, 2009
5,177
1,285
Conventional math requires that the value under a square root and its result are positive numbers.

For example:
$\sqrt{(-5)^2}=|-5|=5$

and in general:
$\sqrt{x^2}=|x|$

3. ### RiJoRI Well-Known Member

Aug 15, 2007
536
29
Could it be that what is seen as || should actually be ( ) ?? (Look at the formula above the red-arrow one.

--Rich