why is calculator giving in absolute form?

Thread Starter

PG1995

Joined Apr 15, 2011
816
Hi

Please have a look on the attachment. Could you please tell me why the calculator is giving the answer (arrow points to the answer under discussion) in absolute form? (x^2 - a^2)^2 would always be a +ve number by definition, so in my opinion there was no need to use absolute form. Please help me. Thanks.

Regards
PG
 

Attachments

Georacer

Joined Nov 25, 2009
5,182
Conventional math requires that the value under a square root and its result are positive numbers.

For example:
\(\sqrt{(-5)^2}=|-5|=5\)

and in general:
\(\sqrt{x^2}=|x|\)
 
Top