# why is calculator giving in absolute form?

#### PG1995

Joined Apr 15, 2011
816
Hi

Please have a look on the attachment. Could you please tell me why the calculator is giving the answer (arrow points to the answer under discussion) in absolute form? (x^2 - a^2)^2 would always be a +ve number by definition, so in my opinion there was no need to use absolute form. Please help me. Thanks.

Regards
PG

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#### Georacer

Joined Nov 25, 2009
5,181
Conventional math requires that the value under a square root and its result are positive numbers.

For example:
$$\sqrt{(-5)^2}=|-5|=5$$

and in general:
$$\sqrt{x^2}=|x|$$

#### RiJoRI

Joined Aug 15, 2007
536
Could it be that what is seen as || should actually be ( ) ?? (Look at the formula above the red-arrow one.

--Rich