Where can I get shockley diodes?

Thread Starter

distortedkarl

Joined Oct 2, 2012
5

Thread Starter

distortedkarl

Joined Oct 2, 2012
5
You could perhasp use a DIAC. If you use DC it should not matter much
http://www.allaboutcircuits.com/vol_3/chpt_7/4.html
I've tried looking at the DIAC's here but the lowest breakover voltage is 32V. I need something closer to 3V for breakover voltage. Do these even exist?

I was thinking that i could make my own? Maybe get two diodes and make them into a 4 layer diode by connected one lead of each to the other?
 

MrChips

Joined Oct 2, 2009
30,802
No. Semiconductor devices don't work like that. For the same reason you cannot make a bipolar junction transistor by connecting two diodes together.
 

Thread Starter

distortedkarl

Joined Oct 2, 2012
5
Maybe I'm over thinking the whole thing. I could be wrong but I think I could use regular didoes? A normal diode needs a forward voltage of 0.7V before it can conduct right? So If i put 7 in series the series of diodes would need 4.9 volts to conduct right? Charge a capacitor from high resistance resistor that's connected to a 9 volt battery. Once the capacitor voltage goes above 4.9V the diodes would conduct and discharge the capacitor? Sorry if i'm completely wrong.

Here is a diagram of what i'm trying to say https://docs.google.com/drawings/d/1cer4FLtmnJf97PR1RZ4e2YwltqOasCnku6yC6zysiuI/edit
 

Audioguru

Joined Dec 20, 2007
11,248
A bunch of diodes in series or a zener diode simply clamps the capacitor voltage at one voltage.

A Shockley diode (small signal ones are no longer made) breaks down and shorts the capacitor voltage to ground then opens, allowing the circuit to oscillate in a sawtooth waveform.

Many years ago I used a PUT (programmable unijunction transistor) to do the same thing. Look at it in Google or see the datasheet for a 2N6027.
You can also use two transistors if you want.
Today, Digikey has more than 100,000 2N6027 PUTs in stock for $.44 each.
 

Bernard

Joined Aug 7, 2008
5,784
Ordnary diodes donot switch, need something like tunnel diode, unijunction, programable unijunction, etc. Example: PUT 2N6028 with example ckt in thumbnail. Period is close to R*C. For a sawtooth, output is from top of cap. into a high Z .
 

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Thread Starter

distortedkarl

Joined Oct 2, 2012
5
A bunch of diodes in series or a zener diode simply clamps the capacitor voltage at one voltage.

A Shockley diode (small signal ones are no longer made) breaks down and shorts the capacitor voltage to ground then opens, allowing the circuit to oscillate in a sawtooth waveform.

Many years ago I used a PUT (programmable unijunction transistor) to do the same thing. Look at it in Google or see the datasheet for a 2N6027.
You can also use two transistors if you want.
Today, Digikey has more than 100,000 2N6027 PUTs in stock for $.44 each.
Thank you this is what i've been looking for. I've found a YouTube video that Explains how it works too. http://www.youtube.com/watch?v=pSFXuFs7kSA

I wonder why they stopped making Shockley diode's?
 

Thread Starter

distortedkarl

Joined Oct 2, 2012
5
Ordnary diodes donot switch, need something like tunnel diode, unijunction, programable unijunction, etc. Example: PUT 2N6028 with example ckt in thumbnail. Period is close to R*C. For a sawtooth, output is from top of cap. into a high Z .
Thank you for the circuit, this is the type of circuit i was looking for.
 
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