Hi everyone! I need help with a few conceptual questions in regard to semoconductor diodes please bear with me..I have only 4 questions to ask,any help will be greatly appreciated,especially as I have my exams starting next week.
1. Why does the diffusion of carriers during the formation of depletion region (when the p and n type crystals are just put together) stop after a while?---is it because the stationary charges (e.g negatively charged ions/kernels in the p-side) repel the incoming charges?
2.When we say that in reverse bias,the holes in the P-side are attracted to the negative terminal of battery in the P-side,it is equivalent to saying that the minority electrons (that reside in the conduction band of the host semiconductor atoms) move toward the junction...so it's exactly similar to the situation when the electrons from the n-side move in (diffusion current) during depletion layer formation,isn't it?
3.In forward bias, electrons and holes from close to the junction are migrating a short distance and recombining. Since this continually happens, the external circuit appears like a steady current is flowing....this is what it says in my book.
Does this mean that the electrons in the conduction band (i.e the minority carriers in p-side )moving away from the junction ?
Again,there'll be some of these conduction band electrons that cross over into the n side to fill in the vacancies created by the electrons of the n side,which move away from the junction in respone to the applied voltage.....can anyone tell me what exactly the line from my book says?
4.After hole-electron pair generation,in the p-side,does the electron generated cross the potential barrier and enter n-side...I mean if there are accumulation of electrons,there will be an accumulation of negative charges on the p-side,but at the same tome,I don't see how the electrons so generated could move accross the depletion layer into the n-side.
Please do help.
1. Why does the diffusion of carriers during the formation of depletion region (when the p and n type crystals are just put together) stop after a while?---is it because the stationary charges (e.g negatively charged ions/kernels in the p-side) repel the incoming charges?
2.When we say that in reverse bias,the holes in the P-side are attracted to the negative terminal of battery in the P-side,it is equivalent to saying that the minority electrons (that reside in the conduction band of the host semiconductor atoms) move toward the junction...so it's exactly similar to the situation when the electrons from the n-side move in (diffusion current) during depletion layer formation,isn't it?
3.In forward bias, electrons and holes from close to the junction are migrating a short distance and recombining. Since this continually happens, the external circuit appears like a steady current is flowing....this is what it says in my book.
Does this mean that the electrons in the conduction band (i.e the minority carriers in p-side )moving away from the junction ?
Again,there'll be some of these conduction band electrons that cross over into the n side to fill in the vacancies created by the electrons of the n side,which move away from the junction in respone to the applied voltage.....can anyone tell me what exactly the line from my book says?
4.After hole-electron pair generation,in the p-side,does the electron generated cross the potential barrier and enter n-side...I mean if there are accumulation of electrons,there will be an accumulation of negative charges on the p-side,but at the same tome,I don't see how the electrons so generated could move accross the depletion layer into the n-side.
4.After hole-electron pair generation,in the p-side,does the electron generated cross the potential barrier and enter n-side?
Please do help.