If your load draws 2 amperes when it's connected to a 12 volt source and you only have a 9 volt source, then you'll need to connect a boost converter between your 9 volt source and your 12 volt load in order to convert that 9 volts to 12 volts.Thanks a lot for all the answers. sorry for asking this much basic question.
What i basically want to know that, I want 12v@2amps dc for my device.
*If i will use a 9v dc battery , Will it work for even for quite some time?
* If i will double the battery in parallel then what will happen ? if I will do the same in serial then ? which way will be batter. ?
Then there's power (P), which is the product of current (I) and voltage (V), so your load will dissipate:
P = IE = 2A X 12 V = 24 watts.
On top of that, nothing is perfect so if your boost converter puts out 24 watts and it's, say, 80% efficient, it'll need to see Pin = Pout / 0.8 = 30 watts on its input.
With a 9 volt source, the input current required to get 30 watts into the boost converter will be:
I = P / E = 20W / 9V = 2.2 amperes.
Now, if you know for how long you want to run your load, and you want to run it from a battery, you can select the battery you need by knowing its capacity (C) at the rate current is taken from it.
For example, if you want to run your load for one hour, the battery's capacity must be such that it can supply the current needed by the boost converter's input until the battery voltage falls below the voltage needed to run the boost converter, which will be something greater than 2.2 ampere hours at 1C.
So... Why can't you just use something like a 12 volt sealed lead - acid battery to run your widget and make life a little easier?
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