The current through an initially uncharged 4uF capacitor is as attached. Find the voltage across the capacitor for 0<t<3.
I have following calculation:
i = 40mA 0 <t < 1
i = 0 1 < t < 2
i = 40mA 2 < t < 3
since the voltage across capacitor is given by:
v = (1/c) ∫ i dt + v(t0)
v (@40mA) = (1/c) ∫40m dt + 0 = 10t KV
v(@0mA) = (1/c) ∫0m dt + 10KV = 10KV
v(@ 40mA) = (1/c) ∫40m + 10KV = 10t + 10 KV
But it seems v(@40mA) is wrong and also understand I am missing something but do not know where exactly and how.
I will appreciate the pointers.
I have following calculation:
i = 40mA 0 <t < 1
i = 0 1 < t < 2
i = 40mA 2 < t < 3
since the voltage across capacitor is given by:
v = (1/c) ∫ i dt + v(t0)
v (@40mA) = (1/c) ∫40m dt + 0 = 10t KV
v(@0mA) = (1/c) ∫0m dt + 10KV = 10KV
v(@ 40mA) = (1/c) ∫40m + 10KV = 10t + 10 KV
But it seems v(@40mA) is wrong and also understand I am missing something but do not know where exactly and how.
I will appreciate the pointers.
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