Hello,
I've got a very basic question, apologies.
There are two photos attached, one is a scan of the
circuit diagram, the other is a photo of the components
assembled. My question is: what exactly is going on
in this circuit?
If the probe (yellow wire) touches the 9v socket, then
I'm guessing the current runs from there through the
10k resistor to the meter where it reads nearly
one mA (new batteries) (9/10k); then through the blue wire
to ground.
If the probe touches the junction of R1 and R2 then
I'm guessing that current flows from the 9v socket
through the 1k resistor to the yellow wire and then
as above. The meter reads close to 5 mA here. This
I don't understand, since the 1k and 10k resistors
are in series, aren't they? And total resistance in
the circuit would then be 11k, so I'm obviously
mixed up here.
Finally if the probe touches ground there's no reading
on the meter; I don't understand why that is either, or
even really how the 2nd 1k resistor is involved in
the circuit.
Thanks very much for any help,
Gerard
I've got a very basic question, apologies.
There are two photos attached, one is a scan of the
circuit diagram, the other is a photo of the components
assembled. My question is: what exactly is going on
in this circuit?
If the probe (yellow wire) touches the 9v socket, then
I'm guessing the current runs from there through the
10k resistor to the meter where it reads nearly
one mA (new batteries) (9/10k); then through the blue wire
to ground.
If the probe touches the junction of R1 and R2 then
I'm guessing that current flows from the 9v socket
through the 1k resistor to the yellow wire and then
as above. The meter reads close to 5 mA here. This
I don't understand, since the 1k and 10k resistors
are in series, aren't they? And total resistance in
the circuit would then be 11k, so I'm obviously
mixed up here.
Finally if the probe touches ground there's no reading
on the meter; I don't understand why that is either, or
even really how the 2nd 1k resistor is involved in
the circuit.
Thanks very much for any help,
Gerard
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