Calculate the collector voltage Vc as Vin increases from 0-5V and hence plot the transfer characteristic Vc vs Vin (consider many points where Vc is changing rapidly). Calculate Vin when Vc = 2V. An NPN with a gain of B = 100 is used.
Attempt:
When Vin = 0V and 1V Vc = 0.
Vin = 2V: Ib = 2 - 0.7 / 10 x 10^3
= 1.3 x 10^-4
Ic = IbB
= 1.3 x 10^-4 x 1000
= 0.013
Vc = 5 - 0.013 x 1 x 10^3
= -8V
I dont understand why I got a negative answer.
Attempt:
When Vin = 0V and 1V Vc = 0.
Vin = 2V: Ib = 2 - 0.7 / 10 x 10^3
= 1.3 x 10^-4
Ic = IbB
= 1.3 x 10^-4 x 1000
= 0.013
Vc = 5 - 0.013 x 1 x 10^3
= -8V
I dont understand why I got a negative answer.
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