Hello guys.
Im having a problem finding the average value of a specific V(o) function.
Heres the circuit:
When the diode is considered ideal, V(o)=V(i) (for the positive values of Vi) and V(o)=0V (for the negative values of V(i)).
then: \(V_{AVG}=\frac{1}{2\pi }(\int_{0}^{\pi}20\cdot sinwt\cdot d(wt))\)
which can be simplified: \(V_{AVG}=\frac{20}{\pi}\)
But when the diode is considered real, with a 0,7V barrier...
V(i)=20sinwt-0.7
\(V_{AVG}=\frac{1}{2\pi }(\int_{\theta_1}^{\theta_2}20sinwt-0.7\cdot d(wt))\)
How to solve this integral !
Im having a problem finding the average value of a specific V(o) function.
Heres the circuit:
When the diode is considered ideal, V(o)=V(i) (for the positive values of Vi) and V(o)=0V (for the negative values of V(i)).
then: \(V_{AVG}=\frac{1}{2\pi }(\int_{0}^{\pi}20\cdot sinwt\cdot d(wt))\)
which can be simplified: \(V_{AVG}=\frac{20}{\pi}\)
But when the diode is considered real, with a 0,7V barrier...
V(i)=20sinwt-0.7
\(V_{AVG}=\frac{1}{2\pi }(\int_{\theta_1}^{\theta_2}20sinwt-0.7\cdot d(wt))\)
How to solve this integral !
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