Hi everyone:

Thanks so much for your help with my previous questions.

A'B+B'C'+AB+B'C=1

The problem is to prove the identity of that equation. I solved it out, please tell me if I did it correctly. Thanks!

A'B+AB+B'C'+B'C=1 (equation re-arranged)
B(A'+A)+B'(C'+C)= 1
B(1)+B'(1)=1
B+B'=1
1=1

Thanks in advance for your replies!!

 

Yep, that's all there is!

 

Thanks for checking over it for me!