# understanding power dissipation

#### ian123

Joined Aug 24, 2011
73
hi there

I have a mosfet h bridge design which works with a passive load of 3 amps @300vdc.

therefore p=v x i = 300 x 3 = 900 watts

so the whole circuits power disspation = 900 watts

how do i work out the power going through the mosfets?

is it 900 watts or is it P=I² x Rdson = 3² x 0.27 = 2.43 watts

which means that 2.43 watts is going through the mosfets and the rest in the passive load??

#### SgtWookie

Joined Jul 17, 2007
22,227
You have 2.43 Watts being dissipated in a MOSFET. Since you say it's an H-bridge, and if all of the MOSFETs are identical, you will have 2.43 Watts dissipated in one high side and another 2.43 Watts in one low side MOSFET, for a total of 4.86 Watts. Then subtract that from the 900 Watts to get 895.14 Watts power being dissipated in the load.

#### ian123

Joined Aug 24, 2011
73
You have 2.43 Watts being dissipated in a MOSFET. Since you say it's an H-bridge, and if all of the MOSFETs are identical, you will have 2.43 Watts dissipated in one high side and another 2.43 Watts in one low side MOSFET, for a total of 4.86 Watts. Then subtract that from the 900 Watts to get 895.14 Watts power being dissipated in the load.
So in order to calculate the heatsink for the mosfets i can get a heatsink 200°c per watt per meter

therefore a 60mm heatsink would do for the two mosfets and a 12mm lenght for four mosfets?