Alrighty, my next question ...
I've looked around the web, and have thus far not found the appropriate answer. Most of the answers to the question seem opposite of my intention.
My question: How to drop voltage? Say I have a 9 volt battery that I want to drop to 5v?. I start out with (9 (starting volts)-5 (desired volts))=I*R, right? I may not have a circuit to be powered by it at the time, I may just want to make the supply for future use in projects I haven't yet built or designed. So I don't know the presumed consumed I (amps) for the calculation.
What's the best method for obtaining the resistance? Just toss ohms at it until the numbers are correct?
I'm assuming some known I values for the heck of it:
4=.5(I)*8(r) would be 8ohms resistance for anything less than 500mA at 5V?
4=1(I)*4(r)=4ohms resistance for anything drawing less than 1A at 5V?
What happens if I plug the 5V 1A supply into a circuit that only draws 250mA? Then wouldn't my 5V actually become 20V, per Ohm's Law? And if that's the case, how would I go about keeping the voltage at 5v so I don't fry the 250mA circuit?
But wait, here's a snag, how would I be providing 20V from a 9V source?
I've looked around the web, and have thus far not found the appropriate answer. Most of the answers to the question seem opposite of my intention.
My question: How to drop voltage? Say I have a 9 volt battery that I want to drop to 5v?. I start out with (9 (starting volts)-5 (desired volts))=I*R, right? I may not have a circuit to be powered by it at the time, I may just want to make the supply for future use in projects I haven't yet built or designed. So I don't know the presumed consumed I (amps) for the calculation.
What's the best method for obtaining the resistance? Just toss ohms at it until the numbers are correct?
I'm assuming some known I values for the heck of it:
4=.5(I)*8(r) would be 8ohms resistance for anything less than 500mA at 5V?
4=1(I)*4(r)=4ohms resistance for anything drawing less than 1A at 5V?
What happens if I plug the 5V 1A supply into a circuit that only draws 250mA? Then wouldn't my 5V actually become 20V, per Ohm's Law? And if that's the case, how would I go about keeping the voltage at 5v so I don't fry the 250mA circuit?
But wait, here's a snag, how would I be providing 20V from a 9V source?