ULN2003 Enable

SgtWookie

Joined Jul 17, 2007
22,230
Well, perhaps you could use an N-ch logic-level MOSFET to interrupt the GND pin connection. If Vgs=0 on the MOSFET, then there would not be a direct ground path for the Darlingtons to sink current to; as long as the ULN2003's common cathode were either disconnected or connected to the +V supply.
 

Thread Starter

JK-FlipFlop

Joined Jul 5, 2010
111
Thank you,
I really thought about using MOSFET to turn off the chip, but are you sure that there isn't anything else equivalent? but with enable...

I prefer using one with enable pin built in.

for debugging I will use the mosfet switch meanwhile.
 

THE_RB

Joined Feb 11, 2008
5,438
Add a cheap 1N4148 diode to each base input pin.

Then the cathodes of the diodes are all connected together, let's call that point A.

When you ground point A it ties all the bases to 0.7v so all drivers in the IC will be off, as they are darlingtons and need about 1.2v to turn on.

Depending on what you are using to drive the bases you might also need a series resistor on each base pin.
 

minhle

Joined Jun 1, 2011
6
as mensioned above, 2003 is a driver, so you need cd4017 so that it can drive 2003. the 4017 has a reset pin.

hope it can help
 
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