Hi All
If any of you teach, and if you ever write tutorials or books, please, please don't assume we understand - we don't!
Now that I have vented please let me explain. I am reading about the attached amp circuit and one part poses a question:
Q. Trace the path for the d-c component of plate current for tube V2
A. The d-c path is from ground (the negative side of the power supply) through R5, through the tube, through R6 to the positive side of the power supply, and through the supply back to ground.
Hmmmm. "...and through the supply back to ground". Hmmmm. If you look a Ebb (which I assume us the supply) the positive and negative path are open! Only a-c can pass to the negative side and not d-c!
So, can someone please explain how dc can go "through the supply back to ground" when the + and - are open
If any of you teach, and if you ever write tutorials or books, please, please don't assume we understand - we don't!
Now that I have vented please let me explain. I am reading about the attached amp circuit and one part poses a question:
Q. Trace the path for the d-c component of plate current for tube V2
A. The d-c path is from ground (the negative side of the power supply) through R5, through the tube, through R6 to the positive side of the power supply, and through the supply back to ground.
Hmmmm. "...and through the supply back to ground". Hmmmm. If you look a Ebb (which I assume us the supply) the positive and negative path are open! Only a-c can pass to the negative side and not d-c!
So, can someone please explain how dc can go "through the supply back to ground" when the + and - are open
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