A coil and 2 capacitors are connected in parallel. If the inductance of the coil is 100 uH and the fixed capacitance C1 is 80 pF, what should be C2 to tune in a broadcast frequency of 1000 kHz?

Here is what I was thinking:

C1 and C2 are in parallel, so their combined capacitance is C1 + C2.

A resonant circuit has maximum current when 2πfL = 1/(2πfC), or

C = 1/((2πf)^2L)

Since C = C1 + C2

C2 = 1/(2πf)^2L) - C1

Is this right?