Trouble with the equation for a half-wave rectifer with an RL load

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Discussion in 'Homework Help' started by hunterage2000, Dec 6, 2011.

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  1. Dec 6, 2011 #1
    hunterage2000

    Thread Starter Active Member

    May 2, 2010
    438
    1
    Can someone explain to me how to use the attached equation?

    How is the value of alpha, theta and q found?
     
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  2. Dec 6, 2011 #2
    Georacer

    Moderator

    Nov 25, 2009
    5,151
    1,266
    Symbolism differs between authors and years. Can you post the context of this equation or a reference to it?
     
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  3. Dec 7, 2011 #3
    hunterage2000

    Thread Starter Active Member

    May 2, 2010
    438
    1
    I am trying to calculate the load current of a Single-Phase RL Half-wave rectifier with
    parameters of:

    R = 10
    L = 31.8mH
    alpha = 45
    theta = 2*pi*50
    q = 0.999

    and I am plugging in these values into the equation and I am getting a negative value of 24. I am not sure if I am putting it into the calculator correctly.
     
    #3 Reply
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