Trouble with the equation for a half-wave rectifer with an RL load

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Discussion in 'Homework Help' started by hunterage2000, Dec 6, 2011.

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Dec 6, 2011 #1

hunterage2000 Thread Starter Senior Member

May 2, 2010

471

1
Can someone explain to me how to use the attached equation?

How is the value of alpha, theta and q found?
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Dec 6, 2011 #2

Georacer Moderator

Nov 25, 2009

5,181

1,289

Symbolism differs between authors and years. Can you post the context of this equation or a reference to it?

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Dec 7, 2011 #3

hunterage2000 Thread Starter Senior Member

May 2, 2010

471

1

I am trying to calculate the load current of a Single-Phase RL Half-wave rectifier with
parameters of:

R = 10
L = 31.8mH
alpha = 45
theta = 2*pi*50
q = 0.999

and I am plugging in these values into the equation and I am getting a negative value of 24. I am not sure if I am putting it into the calculator correctly.

#3 Like Reply

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