# Trivial RL Transient Circuit Question...

#### blah2222

Joined May 3, 2010
582
Hi, so this is so trivial, but I just can't grasp it.

I have the circuit below:

The switch opens at t = 0, and I am trying to find $$I_{L}(0^{-})$$.

Assumed that the circuit has been closed for a long time, so the inductor is a short. Based on this, the circuit turns into this:

I thought that $$I_{L}(0^{-})$$ would be 6 A, (5 + 1), but it is not and I'm not really sure how this works. Isn't the short technically just ground?

Bah, oh well, anyone lend a hand?

Thanks,
JP

#### t_n_k

Joined Mar 6, 2009
5,455
I agree that the inductor current at t=0 would be 6A. It's quite clear this would be true - so I'm not sure what answer is stated elsewhere as being correct.