He knew to do this from experience. This is a well known trig substitution method. This would not be obvious to a student new to the subject.he drew the triangle out because he needed to solve the integral of "8*sqrt(9-x^2)"....
so how did he derive and get that triangle just from looking at this equation? or maybe can you explain and solve the integral of "8*sqrt(9-x^2)"?
also, when can i apply this formula? and how would i know that "sqrt(9-x^2)" is on the adjacent of the triangle? why can't it be on the opposite?
Generally, you have the following options.are there any alternative to solve this integration?
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by Rushi Patel
by Luke James