Trigonometry of the right triangle

Discussion in 'Math' started by paul_alan, Nov 27, 2011.

1. paul_alan Thread Starter Member

Nov 5, 2011
43
0
I'm a new Biomedical Tech student and we're working with Trigonometry of the right triangle right now and I have a problem I can't figure out: If a = x, c = 2x : find the Sine, Cosine and Tangent for angles a and b. How do you determine the value for x?

2. hgmjr Retired Moderator

Jan 28, 2005
9,029
219
This appears to be a homework question. If you can confirm this I will move it to the Homework forum.

How about attaching a scan of your effort to solve the problem so that we can see where you are getting snagged.

hgmjr

3. 1chance Member

Nov 26, 2011
42
185
You are focusing on the wrong issue. It doesn't matter what x is. What matters is the ratio of a to c. Sin A = a/c (opp/hyp) or in your case x/2x =>1/2. To find the value of angle A simply use inverse sin of 1/2. You should be aware that sin A = cos B as they are an example of a cofunction. Once you have determined the value of angle A you can use the calculator to find each value (approximated) OR draw the triangle out & use pythagorean's theorem to find the missing side b (letting a = 1 and c= 2 remember everything is proportional) and then you will have the exact values. Obviously, if you want to work with Angle B, it is equal to 90 - Angle A or just use the cofunctions. The big idea in this problem is seeing that Sin A = 1/2.

4. jimkeith Well-Known Member

Oct 26, 2011
539
100
By inspection, it is obviously a 30°, 60°, 90° triangle--take it from there

5. 1chance Member

Nov 26, 2011
42
185
Yes, this is obvious. But you gave him the fish--I was trying to teach him how to fish! 6. jimkeith Well-Known Member

Oct 26, 2011
539
100 Woops--blew that one--at least, I hope he never forgets this one...