Hey everyone, i have a little problem here. When we use a voltage divider bias configuration and i don't understand why the base voltage of the transistor is exactly the same as the voltage on the second voltage divider resistor. Isn't the base of the transistor in paralel with the second resistor and comporting like some kind of load? Please check this short little video. Thank you for your answering!
http://www.youtube.com/watch?v=cbvUMOmUgaM
http://www.youtube.com/watch?v=cbvUMOmUgaM